The highest power of 2 by which the product of first 100 counting numbers can be divided without any remainder is .......
A
97
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B
96
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C
95
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D
94
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Solution
The correct option is A97 The highest power of a number x contained in n is [n∖x]+[n∖x2]+[n∖x3]+........tillbecomes0 n=100 x=2 So total power⇒[100∖2]+[100∖4]+[100∖8]+[100∖16]+[100∖32]+[100∖64] ⇒50+25+12+6+3+1=97 Hence, option 'A' is correct.