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Question

The highest power of 2 by which the product of first 100 counting numbers can be divided without any remainder is .......

A
97
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B
96
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C
95
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D
94
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Solution

The correct option is A 97
The highest power of a number x contained in n is
[nx]+[nx2]+[nx3]+........tillbecomes0
n=100
x=2
So total power[1002]+[1004]+[1008]+[10016]+[10032]+[10064]
50+25+12+6+3+1=97
Hence, option 'A' is correct.

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