CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The highest power of 2 by which the product of first 100 counting numbers can be divided without any remainder is .......

A
97
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
96
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
95
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
94
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 97
The highest power of a number x contained in n is
[nx]+[nx2]+[nx3]+........tillbecomes0
n=100
x=2
So total power[1002]+[1004]+[1008]+[10016]+[10032]+[10064]
50+25+12+6+3+1=97
Hence, option 'A' is correct.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Arithmetic Progression
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon