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Question

The horizontal and vertical displacement x and y of a projectile at a given time t are given by x=6t metre and y=8t -5t2 metre. The range of the projectile in metre is.

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Solution

Y=8t5t2

From this equation

uSinθ=8

x=6t

From this equation

uCosθ=6

Square and add equations (1) and (2)

u²(Sin²θ+Cos²θ)=8²+6²

u²=100

u=10m/s

Velocity of projection is 10m/s


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