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Helical Motion

The horizonta...

Question

The horizontal component of the earth's magnetic field at a place is $B$ and angle of dip is $60^{\circ}$ . What is the value of horizontal component of earth magnetic field at equator?

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Solution

We have, Horizontal earth magnetic field
$B_{H} = B$
Angle of dip= $60 °$
Therefore vertical magnetic field $= ? = B_{V}$
Using $tan θ = \frac{B_{V}}{B_{H}}$
$⟹ B_{V} = B_{H} tan 60 °$

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