wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The horizontal range and maximum height for a projectile is same. The angle of projectile is

A
θ=tan1(14)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
θ=tan1(4)
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
θ=tan1(2)
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
θ=45°
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B θ=tan1(4)
Let angle of projection be θ
We know,
Maximum height = u2sin2θ2g
Horizontal range = u2sin2θg
According to question

u2sin2θ2g=u2sin2θg
sin2θ2=2sinθcosθ
tanθ=4
θ=tan1(4)

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Jumping Off Cliffs
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon