Question

The horizontal range of a projectile fired at an angle of 15° is 50 m. If it is fired with the same speed at an angle of 45°, its range will be:

• A. 60 m
• B. 71 m
• C. 100 m
• D. 141 m

Answer 1

The correct option is C 100 m

The horizontal range of a projectile fixed at an angle$=15°$

Range$=50m$

In dirst case range$=50=u^2/g(\sin 2\times 15°)$

$50=\frac{{}^2}{2g}\frac{u^2}{g}=100$

In 2nd case range$=\frac{u^2}{g(\sin 2\times 45°)}=\frac{100}{1}(\because \sin 90°=1)=100m$