Question

The horizontal range of a projectile is $4\sqrt{3}$ times its maximum height. Its angle of projection will be

• A. ${45}^{\circ }$
• B. ${60}^{\circ }$
• C. ${90}^{\circ }$
• D. ${30}^{\circ }$

Answer 1

The correct option is D ${30}^{\circ }$

$R=4Hcot\theta ,IfR=4\sqrt{3}H$ then $cot\theta =\sqrt{3}\Rightarrow \theta ={30}^{\circ }$