Question

The horizontal range of a projectile is maximum for a given velocity of projection when the angle of projection is :

• A. ${30}^o$
• B. ${60}^o$
• C. ${45}^o$
• D. ${90}^o$

Answer 1

Answer: (C)

${45}^o$

$R=\frac{u^{2}sin2\theta }{g}$
sin $2\theta$ is maximum $={90}^o,\therefore 2\theta ={90}^o,so\theta ={45}^o$