The human heart forces $4 \times 10^{- 3} m^{3}$ of blood per minute through the arteries under a pressure of $0.13$ m. Calculate the horsepower of the heart. The density of blood is $1.03 \times 10^{3}$ kg $m^{- 3}$ . Take $g = 9.8 m s^{- 2}$ and $1$ H.P. $= 746$ W.

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Solution

Given data
Volume $- (V) = 4 \times 10^{- 3} m^{3}$
$(h) = .13 m$
density $(f) = 1.03 \times 10^{3} k g m^{- 3}$
$(g) = 9.8 m / s e c^{2}$
$P = f g h$
$\Rightarrow 1.03 \times 10^{3} \times 9.8 \times .13$
$= (9.8) (1.03) (.13) \times 10^{2}$
$P = 1312.22 P a$
$t = 1 m i n u t e = 60 s e c$
Power $\frac{w}{t} = \frac{F_{s}}{t} = \frac{F_{A S}}{A t} = \frac{P_{v}}{t}$
Power $= \frac{1312.22 \times 4 \times 10^{- 3}}{60 \times 746} W$
$P = 1.17 \times 10^{- 4} h p$

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The human heart forces 4×10−3m3 of blood per minute through the arteries under a pressure of 0.13m. Calculate the horsepower of the heart. The density of blood is 1.03×103kg m−3. Take g=9.8ms−2 and 1 H.P. =746W.

Given data Volume −(V)=4×10−3m3(h)=.13mdensity (f)=1.03×103kgm−3(g)=9.8m/sec2P=fgh⇒1.03×103×9.8×.13=(9.8)(1.03)(.13)×102P=1312.22Pat=1minute=60secPower wt=Fst=FASAt=PvtPower =1312.22×4×10−360×746WP=1.17×10−4hp

The human heart forces $4 \times 10^{- 3} m^{3}$ of blood per minute through the arteries under a pressure of $0.13$ m. Calculate the horsepower of the heart. The density of blood is $1.03 \times 10^{3}$ kg $m^{- 3}$ . Take $g = 9.8 m s^{- 2}$ and $1$ H.P. $= 746$ W.