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Magnetic Moment Examples

The hybrdisat...

Question

The hybrdisation of the complex $F e (C O)_{5}$ is :

A

s p^{3} d^{2}

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B

d s p^{3}

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C

s p^{3}

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D

d^{2} s p^{3}

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Solution

The correct option is B $d s p^{3}$
$F e (C O)_{5} - F e - [A r] 3 d^{6} 4 s^{2} - d s p^{3}$ hybridization.

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Similar questions

The hybrdisation of the complex $[N i C l_{4}]^{- 2}$ is:

The hybrdisation of the complex $[C u (N H_{3})_{4}]^{+ 2}$ is :

s p^{3} d^{2}

hybridization the same as

d^{2} s p^{3}

Q. Match each set of hybrid orbitals from LIST-I with complex(es) given in LIST-II.

LIST - I	LIST - II
P. $d s p^{2}$	1. $[F e F_{6}]^{4 -}$
Q. $s p^{3}$	2. $[T i (H_{2} O)_{3} C l_{3}]$
R. $s p^{3} d^{2}$	3. $[C r (N H_{3})_{6}]^{3 +}$
S. $d^{2} s p^{3}$	4. $[F e C l_{4}]^{2 -}$
	5. $[N i (C O)_{4}]$
	6. $[N i (C N)_{4}]^{2 -}$

The correct option is:

Q. Assertion :Transition metal ion forming octahedral complexes undergo

s p^{3} d^{2}

d^{2} s p^{3}

hybridisation. Reason: Strong field ligands force the unpaired electrons of central metal ion to pair up causing

d^{2} s p^{3}

hybridisation whereas weak field ligands do not affect electronic configuration of the metal ion undergoes in

s p^{3} d^{2}

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