The hybridisation of atomic orbitals of nitrogen in ${N O_{2}}^{+}$ , ${N O_{3}}^{-}$ and ${N H_{4}}^{+}$ are:

sp, ${s p}^{3}$ and ${s p}^{2}$ respectively

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sp, ${s p}^{2}$ and ${s p}^{3}$ respectively

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${s p}^{2}$ ,sp and ${s p}^{3}$ respectively

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${s p}^{2}$ , ${s p}^{3}$ and sp respectively

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Solution

The correct option is B
sp, ${s p}^{2}$ and ${s p}^{3}$ respectively

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Similar questions

The hybridisation of atomic orbitals of nitrogen in ${N O_{2}}^{+}$ , ${N O_{3}}^{-}$ and ${N H_{4}}^{+}$ are:

s p^{3}

N O_{2}^{+}, N O_{3}^{-} a n d N H_{4}^{+}, N F_{3}

N

N O_{2}^{+}, N O_{3}^{-}

N H_{4}^{+}

N O_{2}^{+}, N O_{3}^{-}, and N H_{4}^{+}

N O_{3}^{-}, N O_{2}^{+}, N H_{4}^{+}

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