The hybridisation scheme for the central atom includes a $d$ -orbital contribution in :

I_{3}^{-}

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P C l_{3}

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{N O}_{3}^{-}

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H_{2} S e

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Solution

The correct option is A $I_{3}^{-}$
In $I_{3}^{-}$ , central atom is $s p^{3} d$ hybridised, so d orbitals takes part in hybridisation.

Hence the correct option is A.

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Similar questions

The hybridisation of atomic orbitals of nitrogen in ${N O_{2}}^{+}$ , ${N O_{3}}^{-}$ and ${N H_{4}}^{+}$ are:

N

N O_{2}^{+}, N O_{3}^{-}

N H_{4}^{+}

N O_{3}^{-}

C O_{3}^{2 -}

N O_{3}^{-}

C O_{3}^{2 -}

s p^{2}

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