Question

The hybridization and magnetic nature of ${\left[Mn{\left(CN\right)}_6\right]}^{4-}$ and ${\left[Fe{\left(CN\right)}_6\right]}^{3-}$ , respectively are

• A. $s{p}^3{d}^2$ and diamagnetic
• B. $d^{2}s{p}^3$ and paramagnetic
• C. $d^{2}s{p}^3$ and diamagnetic
• D. $s{p}^3{d}^2$ and paramagnetic

Answer 1

The correct option is B $d^{2}s{p}^3$ and paramagnetic

(i) ${\left[Mn{\left(CN\right)}_6\right]}^{4-}$

$M{n}^{2+}=3d^{5}4s^0$

$C{N}^{-}$ is a strong field ligand

$\therefore$ pairing will occur


It has one unpaired electron so it is paramagnetic.

(ii) ${\left[Fe{\left(CN\right)}_6\right]}^{3-}$

$F{e}^{3+}=3d^{5}4s^0$

$C{N}^{-}$ is a strong field ligand

$\therefore$ pairing will occur

It has one unpaired electron so it is paramagnetic.