The hybridization and shape of $X e F_{2}$ is :

s p^{3}, b e n t

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d s p^{2}, l i n e a r

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s p^{3} d^{2}, l i n e a r

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s p^{3} d, l i n e a r

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Solution

The correct option is D $s p^{3} d, l i n e a r$
$s p^{3} d$ hybridization and linear shape.

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Similar questions

X e F_{2}, X e F_{3}^{+}, X e F_{4}, X e F_{6}

	Molecule	Hybridization	Shape	Number of lone pairs of electrons
$(1)$	$X e O_{3}$	$s p^{3}$	pyramidal	$1$
$(2)$	$X e F_{4}$	$s p^{3} d^{2}$	planar	$3$
$(3)$	$X e F_{2}$	$s p^{3} d$	linear	$2$
$(4)$	$X e O_{4}$	$s p^{3} d^{2}$	pyramidal	$1$

(i)	$X e F_{2}$	(a)	Central atom is $s p^{3}$ hybridised and has a bent shape.
(ii)	$N_{3}^{-}$	(b)	Central atom is $s p^{3} d^{2}$ hybridised and has an octahedral shape.
(iii)	$P C l_{6}^{-}$	(c)	Central atom is $s p$ hybridised and has a linear shape.
(iv)	$I C l_{2}^{+}$	(d)	Central atom is $s p^{3} d$ hybridised and has a linear shape.

What is the hybridization of P in $P C l_{5} (s)$ ?

[N i C l_{4}]^{2 -}, [N i (C N)_{4}]^{2 -} & [N i (C O)_{4}]

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