Question

The hybridization state of the central atom in $PC{l}_5$ is:

• A. $s{p}^{3}d$
• B. $s{p}^3{d}^2$
• C. $s{p}^3$
• D. $d^{2}s{p}^3$

Answer 1

The correct option is A $s{p}^{3}d$

The hybridization state of the central atom in $PC{l}_5$ is $s{p}^{3}d$
Count the bonds and lone pairs about the atom
In $s{p}^{3}d$ there are $5$ bonds ,so the hybridization is $s{p}^{3}d$
Hence option $A$ is correct.