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Electronegativity and Hybridisation

The hybridiza...

Question

The hybridizations of atomic orbitals of nitrogen in $N O_{2}^{+}, N O_{3}^{-}$ and $N H_{4}^{+}$ respectively are

s p, s p^{2}

and

s p^{3}

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s p^{2}, s p

and

s p^{3}

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s p, s p^{3}

and

s p^{2}

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s p^{2}, s p^{3}

and

s p

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Solution

The correct option is A $s p, s p^{2}$ and $s p^{3}$
$\begin{matrix} N O_{2}^{+} = s p & Linear N O_{3}^{-} = s p^{2} & Trigonal planar N H_{4}^{+} = s p^{3} & Tetrahedral \end{matrix}$

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Similar questions

N O_{2}^{+}, N O_{3}^{-}

N H_{4}^{+}

N O_{2}^{+}

N O_{3}^{-}

N H_{4}^{+}

N O_{2}^{+}

N O_{3}^{-}

N H_{4}^{+}

N O_{2}^{-}, N O_{2}^{+} and N H_{4}^{+}

s p^{3}

N O_{2}^{+}, N O_{3}^{-} a n d N H_{4}^{+}, N F_{3}

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