The hydride ion $H^{-}$ is stronger base than its hydroxide ion $O H^{-}$ . Which of the following reaction will occur if sodium hydride is dissolved in water?

H_{(a q)}^{-} + H_{2} O \to H_{3} O^{+}

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H_{(a q)}^{-} + H_{2} O \to O H^{-} + H_{2}

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H^{-} + H_{2} O \to H_{2} + O_{2}

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H^{-} + H_{2} O \to

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Solution

The correct option is C $H_{(a q)}^{-} + H_{2} O \to O H^{-} + H_{2}$
When sodium hydride is dissolved in water:

$N a H + H_{2} O ⟶ N a O H + H_{2}$
$(A q)$

OR

$H^{-} + H^{+} O H^{-} ⟶ O H^{-} + H_{2}$

Hence option B is correct.

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Similar questions

Q. Consider the following reactions,
(i)

{C O}_{3}^{2 -} + H_{2} O ⇌ {H C O}_{3}^{-} + {O H}^{-}

(ii)

{C O}_{2} + H_{2} O ⇌ H_{2} {C O}_{3}

(iii)

{N H}_{3} + H_{2} O ⇌ {N H}_{4} O H

(iv)

H C l + H_{2} O ⇌ {C l}^{-} + H_{3} O^{+}

Which of the pairs of reaction proves that water is amphoteric in character?

Q. Decreasing order of relative nucleophilicity of the following nucleophiles in protic solvent is -

⊖ S H, A C ⊖ O, P h ⊖ O, ⊖ O H, H_{2} O

C H_{3} C O O H + O H^{-} ⇋ C H_{3} C O O^{-} + H_{2} O + q_{1}

and

H^{+} + O H^{-} ⇋ H_{2} O + q_{2}

Then what is the enthalpy for reaction ?

C H_{3} C O O H ⇋ C H_{3} C O O^{-} + H^{+}

Which of the following is not correct?

$O r d e r o f b a s i c i t y O r d e r o f n u c l e o p h i l i c i t y (a) F^{-} > C l^{-} > B r^{-} B r_{-} > C l^{-} > F^{-} (b) H - O - O^{-} > O H^{-} H - O - O^{-} > O H^{-} (c) C H_{3} > N H_{2}^{-} > O H - C H_{3} > N H_{2}^{-} > O H^{-} (d) H_{2} O > H_{2} S H_{2} O < H_{2} S$

H_{2} O + H_{2} O ⇌ H_{3} O^{+} + {O H}^{-}

The above reverse reaction is an exothermic reaction. What will happen if the temperature is lowered?

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The hydride ion H− is stronger base than its hydroxide ion OH−. Which of the following reaction will occur if sodium hydride is dissolved in water?

The correct option is C H−(aq)+H2O→OH−+H2When sodium hydride is dissolved in water:NaH+H2O⟶NaOH+H2(Aq) ORH−+H+OH−⟶OH−+H2Hence option B is correct.

The hydride ion $H^{-}$ is stronger base than its hydroxide ion $O H^{-}$ . Which of the following reaction will occur if sodium hydride is dissolved in water?

The correct option is C $H_{(a q)}^{-} + H_{2} O \to O H^{-} + H_{2}$
When sodium hydride is dissolved in water:

$N a H + H_{2} O ⟶ N a O H + H_{2}$
$(A q)$

OR

$H^{-} + H^{+} O H^{-} ⟶ O H^{-} + H_{2}$

Hence option B is correct.