The hydrocarbon shown below is allowed to react(separately)with two sets of reducing agents.What are the respective products of these reactions?

\begin{matrix} N a / l i q . N H_{3} & H_{2} / P d / C H e p t a n e & H e p t a n e \end{matrix}

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\begin{matrix} T r a n s - t r a n s h e p t a d i e n e & C i s - t r a n s h e p t a d i e n e \end{matrix}

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\begin{matrix} T r a n s - c i s h e p t a d i e n e & C i s - h e p t e n e \end{matrix}

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\begin{matrix} T r a n s - t r a n s h e p t a d i e n e & h e p t a n e \end{matrix}

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Solution

The correct option is D $\begin{matrix} T r a n s - t r a n s h e p t a d i e n e & C i s - t r a n s h e p t a d i e n e \end{matrix}$
Both catalysts are used for hydrogenation of alkynes to an alkene.

Alkyne reduction forms a trans product in the presence of Na in liq. ammonia and cis product in the presence of $H_{2}$ in $P d$
Option B is correct.

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