Question

The hydrolysis constant Kh of a salt of NaOH anda weak acid (HX) if the Ka of the acid is $2\times {10}^{-6}$ is:

• A. $5\times {10}^{-8}$
• B. $5\times {10}^{-6}$
• C. $5\times {10}^{-9}$
• D. $5\times {10}^{-7}$

Answer 1

Answer: (C)

$5\times {10}^{-9}$

Kh=Kw/Ka

Thus Kh=${10}^{-14}$/$2\times {10}^{-6}$ (since Kw=${10}^{-14}$)

$\therefore$ Kh= $5\times {10}^{-9}$