The correct option is B (2,4,4)
Let BC be the given line
Let there be a point D on BC such that OD is perpendicular to BC.
Any general point on BC can be written as (−9+20k,4−4k,5−6k)
Now dr's of BC=(20,−4,−6),
dr's of OD=(−9+20k,4−4k,5−6k)
Since OD is perpendicular to BC,OD.BC=0
−180+400k−16+16k−30+36k=0 i.e k=0.5
Putting the value of k back in D,
D(1,2,2)
Let the image of the origin in line BC be E.
Since E is the mid point of OD we get E to be (2,4,4).