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Question

The image of the origin in the line joining the points (−9,4,5) and (11,0,−1) is

A
(2,4,4)
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B
(1,2,2)
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C
(1,2,3)
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D
(2,2,1)
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Solution

The correct option is B (2,4,4)
Let BC be the given line
Let there be a point D on BC such that OD is perpendicular to BC.
Any general point on BC can be written as (9+20k,44k,56k)
Now dr's of BC=(20,4,6),
dr's of OD=(9+20k,44k,56k)
Since OD is perpendicular to BC,OD.BC=0
180+400k16+16k30+36k=0 i.e k=0.5
Putting the value of k back in D,
D(1,2,2)
Let the image of the origin in line BC be E.
Since E is the mid point of OD we get E to be (2,4,4).

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