The incorrect geometry is represented by:

{N F}_{3}

- trigonal planar

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H_{2} O

- bent

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A s F_{5}

- trigonal bipyramidal

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{B F}_{3}

- trigonal planar

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Solution

The correct option is C ${N F}_{3}$ - trigonal planar
$N F_{3}$ has trigonal pyramidal geometry. N atom has one lone pair and three bond pairs of electrons. The electron pair geometry is tetrahedral and molecular geometry is trigonal pyramidal.

The bond angles are lower than tetrahedral bond angles due to lone pair - lone pair and lone pair-bond pair repulsions. N atom is $s p^{3}$ hybridised.

Hence, option A is the answer.

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Similar questions

What will be the geometry and shape of $N H_{2}^{-}$ ?

[X e F_{5}]^{-}

X e O_{3} F_{2},

X e F_{4}

X e F_{2}, X e F_{4}

X e O_{2} F_{2}

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