Question

The increase in volume of air, when temperature of 600 ml of it, is increased from ${27}^{o}C$ to ${47}^{o}C$ under constant pressure, is

• A. 20 mL
• B. 80 mL
• C. 40 mL
• D. 500 mL

Answer 1

The correct option is C 40 mL

Given: Initial volume ($V_i)=600$, initial temperature=$\left(T_i\right)={27}^{o}C=27+273=300K$, final temperature$\left(T_f\right)={47}^{o}C=27+273=320K$

Solution:

For an isochoric process we can write,

$\frac{V}{T}=constant$

$\Rightarrow \frac{V_i}{T_i}=\frac{V_f}{T_f}$

Putting the given values in the previous equation, we get

$V_f=600\times \frac{320}{300}$

$V_f=640$

$\therefore$ change in volume =640-600=40 ml

Hence the correct option is C.