The increasing order of bond dissociation energies of C - C, C - H and H - H bonds is

H - H < C - H < C - C

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C - C < C - H < H - H

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

H - H < C - C < C - H

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C - H < H - H < C - C

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B
C - C < C - H < H - H

H - H bond energy is the highest due to s-s overlapping (exceptional case)

Suggest Corrections

Similar questions

H_{2} S, N H_{3}, B F_{3}

S i H_{4}

H_{2} S, N H_{3}, B F_{3}

S i H_{4}

The correct order of bond angles (smallest first) in $H_{2} S, N H_{3}, B F_{3}$ and $S i H_{4}$ is-

H_{2}, L i_{2}, B_{2}

H_{2} S, N H_{3}, B F_{3} a n d S i H_{4}

Join BYJU'S Learning Program