wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The increasing order of reducing the power of the halogen acids is


A

HF<HCI<HBr<HI

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B

HI<HBr<HCI<HF

No worries! We‘ve got your back. Try BYJU‘S free classes today!
C

HBr<HCI<HF<HI

No worries! We‘ve got your back. Try BYJU‘S free classes today!
D

HCI < HBr < HF < HI

No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A

HF<HCI<HBr<HI


The explanation for the correct option

(A)HF<HCI<HBr<HI

Reducing the power of the halogen acids

  • As the size of the halogen atom increases, the strength of the H-X bond decreases.
  • So, the tendency to donate hydrogen increases from HF to HI.
  • So, increasing the order of reducing the power of the halogen acids is as follows:-
  • HF<HCI<HBr<HI.

The explanation for the incorrect option

  • The increasing order of reducing the power of the halogen acids is HF<HCI<HBr<HI.
  • Hence, options (B), (C), and (D) are incorrect.

Hence, option (A) is correct. The increasing order of reducing the power of the halogen acids is HF<HCI<HBr<HI.


flag
Suggest Corrections
thumbs-up
7
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Hydrolysis
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon