Question

The increasing order of stability of the following free radicals is .
$1.{{(CH}_3)}_2\dot{CH}<{{(CH}_3)}_3\dot{C}<(C_6{H_5)}_2\dot{CH}<(C_6{H_5)}_3\dot{C}2.(C_6{H_5)}_3\dot{C}<(C_6{H_5)}_2\dot{CH}<{{(CH}_3)}_3\dot{C}<{{(CH}_3)}_2\dot{CH}3.(C_6{H_5)}_2\dot{CH}<(C_6{H_5)}_3\dot{C}<{{(CH}_3)}_3\dot{C}<{{(CH}_3)}_2\dot{CH}4.{{(CH}_3)}_2\dot{CH}<{{(CH}_3)}_3\dot{C}<(C_6{H_5)}_3\dot{C}<(C_6{H_5)}_2\dot{CH}$

Answer 1

Radical is stabilized by $\alpha$ hydrogen. More the $\alpha$-hydrogen more will be hyperconjugation more will be radical stabilization resonance.

Resonance is also a good stabilizing factor and is given preference than hyperconjugation.

So option 1 is correct.