The inductance L (in mH) of the coil which is to be connected in series with a capacitor of 0.3 pF to get anoscillatory resonance frequency of 1 MHz is.
A
8.44mH
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B
84.4mH
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C
844mH
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D
8440mH
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Solution
The correct option is B 84.4mH f=12π1√LC; L=14π2f2C L=14π2×10+12×0.3×10−12 =112=0.0844 =84.4×10−3
= 84.4 mH