The inequality $- x^{2} + x - 10 < - 2 x^{2} - 4$ is satisfied, if

x < - 3

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| x | < 3

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- 3 < x < 2

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- 2 < x < 3

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x < - 3

x > 2

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Solution

The correct option is C $- 3 < x < 2$
Given, $- x^{2} + x - 10 < - 2 x^{2} - 4$
$\Rightarrow x^{2} + x - 6 < 0$
$\Rightarrow (x + 3) (x - 2) < 0$
$\Rightarrow - 3 < x < 2$

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