The infinite series 1-x-x2-2-x3-3-x4-4-x5-5- corresponding to

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Permutation under restriction

The infinite ...

Question

The infinite series $1 + x + \frac{x^{2}}{2!} + \frac{x^{3}}{3!} + \frac{x^{4}}{4!} + \frac{x^{5}}{5!} + . . .$ corresponding to

s e c x

No worries! We‘ve got your back. Try BYJU‘S free classes today!

e^{x}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

c o s x

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1 + s i n^{2} x

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

Suggest Corrections

Similar questions

x_{1}, x_{2}, x_{3}, x_{4}, x_{5}

\sqrt{x_{1} - 1} + 2 \sqrt{x_{2} - 4} + 3 \sqrt{x_{3} - 9} + 4 \sqrt{x_{4} - 16} + 5 \sqrt{x_{5} - 25} = \frac{x_{1} + x_{2} + x_{3} + x_{4} + x_{5}}{2}

\frac{x_{1} + x_{2} + x_{3} + x_{4} + x_{5}}{2}

\int (x + x^{2} + x^{3} + x^{4})

\frac{1}{2} x^{2} + \frac{2}{3} x^{3} + \frac{3}{4} x^{4} + \frac{4}{5} x^{5} + \dots \dots =

f (x) = x - \frac{x^{3}}{3!} + \frac{x^{5}}{5!} - \frac{x^{7}}{7!} + . . . . + \infty

\frac{x + \frac{x^{3}}{3!} + \frac{x^{5}}{5!} + . . . . .}{1 + \frac{x^{2}}{2!} + \frac{x^{4}}{4!} + . . . . .} = \frac{d x - d y}{d x + d y}

Join BYJU'S Learning Program