Question

The initial and final void ratios of a clay sample in a consolidation test are 1 and 0.5, respectively. If initial thickness of the sample is 2.4 cm, then its final thickness will be

• A. 1.3 cm
• B. 1.8 cm
• C. 1.9 cm
• D. 2.2 cm

Answer 1

The correct option is B 1.8 cm

$\frac{H_f}{H_i}=\frac{1+e}{1+e_0}$

$H_f=\left(\frac{1+0.5}{1+1}\right)\times 24$

$=1.5\times 1.2=1.8cm$