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Question

The inner diameter of a circular well is 2.8m. It is 10m deep. Find its inner curved surface area. Also find the cost of plastering this curved surface at the rate of Rs.42 per m2?

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Solution

We know that the curved surface area of a right circular cylinder with radius r and height h is CSA=2πrh.

It is given that the height of the circular well is h=10 m and the diameter of the circular well is 2.8 m, and therefore the radius of the well is 2.82=1.4 m, therefore,

CSA=2πrh=2×227×1.4×10=6167=88 m2

Therefore, the inner curved surface area is 88 m2.

Also, the cost of plastering curved surface per m2 is Rs.42,

Therefore, the cost of plastering 88 m2 is:

Rs.42×88m2= Rs.3696.

Hence, the inner curved surface area is 88 m2 and the cost of plastering curved surface per m2 is Rs.42 is Rs.3696.

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