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Question

The inner diameter of a cylindrical wooden pipe is 24cm and its outer diameter is 28 cm. The length of the pipe is 35cm.Find the mass of the pipe, if 1cm3 of wood has a mass of 0.6g.

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Solution

Inner radius of cylindrical pipe, say r1 = diameter12=242cm=12 cm
Outer radius of cylindrical pipe, say r2 =diameter22=282cm=14 cm
Height of pipe, h = Length of pipe = 35cm
Now, the Volume of pipe = π (r22 - r12) h cm3
Substitute the values.
Volume of pipe = 227×(142122)×35
=110 × 52
= 5720 cm3
Since, Mass of 1 cm3 wood = 0.6 g
Mass of 5720 cm3 wood = (5720 × 0.6) g
= 3432 g or 3.432 kg.

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