Question

The input voltage, $V_i=5+2sin\left(\omega t\right)$ is applied to a circuit as shown in the figure below. Assuming all the elements of the circuit are ideal, then the minimum value of $V_0$ at steady state would be equal to ____

• A. - 5 V
• B. -4 V
• C. -6V
• D. - 3 V

Answer 1

The correct option is B -4 V


For the positive half cycle, the capacitor will charge with a voltage of 5 + 2 = 7 V

The minimum value of the sin function that could be achieved is - 2V, thus the minimum output voltage would be equal to

$V_0$ = 5 - 2 - 7 = -4 V