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Question

The integer k for which the inequality x22(4k1)x+15k22k7>0 is valid for any x, is


A

2

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B

3

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C

4

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D

0

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Solution

The correct option is B

3


x22(4k1)x+15x22k7>0

br4ac<0

4(4k1)2-4.1.(15k2-2k-7)<0

k2-6k+8<0

k ϵ (2,4)

k=3


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