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Stopping Potential

The intensity...

Question

The intensity of incident radiation on a photocell is increased to 4times. Then the number of photoelectrons emitted per second will be

A

Doubled

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B

Halved

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C

Quadrupled

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D

16 times the initial current

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Solution

The correct option is C Quadrupled
Photo-current in photoelectric effect is directly proportional to the intensity of the incident light. So, as intensity is increased to 4 times so,current is increased to 4 times. Now current is number of electrons emitted per second,so as current increase number of electrons ejected per second also increased.
Therefore ,number of electrons ejected per second quadrupled as current or intensity is increased to four times.
So, the answer is option (C).

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