The intermediate during the addition of HCl to propene in the presence of peroxide is

\cdot C H_{3} C H C H_{2} C l

No worries! We‘ve got your back. Try BYJU‘S free classes today!

+ C H_{3} C H C H_{3}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

C H_{3} C H_{2} \cdot C H_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C H_{3} C H_{2} + C H_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $+ C H_{3} C H C H_{3}$

Anti markonvnikov's addition prevails here, due to peroxide. Thus, the product will be propane.

Suggest Corrections

Similar questions

H C l

H C l

H B r

H B r

H B r

Join BYJU'S Learning Program