The internal energy change when a system goes from state $A$ to $B$ is $40 k J m o l e^{- 1}$ . If the system goes from $A$ to $B$ by a reversible path and returns to state $A$ by an irreversible path, what would be the net change in internal energy?

40 k J

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40 k J

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Z e r o

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40 k J

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Solution

The correct option is B $Z e r o$
Internal energy $= △ U = n C_{v} △ T$ (It is a state function i.e independent of it’s path)

Let the state $A$ be $(P_{1}, V_{1}, T_{1})$ and B be $(P_{2}, V_{2}, T_{2})$

When the system goes from $A$ to $B$ (reversibly) and $B$ to $A$ (irreversibly). So, final state comes to be $A (P_{1}, V_{1}, T_{1})$ .

$△ U_{A \to B \to A} = n C_{v} △ T = n C_{v} (T_{2} - T_{1}) = 0$

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