The internal resistance of a primary cell is 4- It generates a current of 0-2 A in an external resistance of 21- The rate at which chemical energy is consumed in providing current is

The resistance of P, Q, R, S arms of a Wheatstone bridge are 5, 15, 20 and $60 Ω$ . A cell of 4volt emf and $4 Ω$ internal resistance is connected with them, then the current flowing ( in ampere) is

Q. A cell of e.m.f.

ε

and internal resistance

r

is used to send current to an external resistance R. The current drawn from the cell is :

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The internal resistance of a primary cell is 4Ω. It generates a current of 0.2A in an external resistance of 21Ω. The rate at which chemical energy is consumed in providing current is

The correct option is B 1J/sPower consumed by a resistance, R=i2RThus, total power cosumed by the circuit =i2R+i2r =i2(R+r)=0.22(4+21)=1 J/s

The internal resistance of a primary cell is $4 Ω$ . It generates a current of $0.2 A$ in an external resistance of $21 Ω$ . The rate at which chemical energy is consumed in providing current is

The correct option is B $1 J / s$
Power consumed by a resistance, $R = i^{2} R$
Thus, total power cosumed by the circuit $= i^{2} R + i^{2} r$
$= i^{2} (R + r) = {0.2}^{2} (4 + 21) = 1 J / s$