The ion which is not tetrahedral in shape is?

B F_{4}^{-}

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N H_{4}^{+}

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[C u (N H_{3})_{4}]^{2 +}

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N i C l_{4}^{2 -}

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Solution

The correct option is C $[C u (N H_{3})_{4}]^{2 +}$
$[C u (N H_{3})_{4}]^{2 +}$ is square planar
Hybridazation state of $C u^{+ 2}$ is $d s p^{2}$

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Similar questions

[N i F_{4}]^{2 +}

{N H}_{4}^{+}

What will be the geometry and shape of $N H_{2}^{-}$ ?

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