Question

The ionic conductivity of $B{a}^{2+}$ and $C{l}^{-}$ at infinite dilution are 127 and 76 respectively. The equivalent conductivity of $BaC{l}_2$ at infinite dilution (in $oh{m}^{-}c{m}^{2}e{q}^{-1}$) would be:

• A. 279
• B. 280
• C. 139.5
• D. 102

Answer 1

Answer: (C)

139.5

Given data,

$\lambda \left(B{a}^{2+}\right)=127$

$\lambda \left(Cl\right)=76$

${\wedge }_m^{\infty }=\lambda \left(B{a}^{2+}\right)+2\lambda \left(Cl\right)$

$=127+2\times 76$

${\wedge }_m^{\infty }=279$

We know that-

${\wedge }_{eq}^{\infty }=\frac{{\lambda }_m^{\infty }\left(B{a}^{2+}\right)}{2}+{\lambda }_m^{\infty }\left(C{l}^{-}\right)$

$=\frac{127}{2}+76$

${\wedge }_{eq}^{\infty }=139.5{ohm}^{-1}{cm}^2$

Hence, option C is correct.