The ionic radius of Na+ ion is 1.02 Å. The ionic radii (in Å) of Mg2+ and Al3+, respectively are:
Answer: (a)
Na+, Mg2+ and Al3+ are isoelectronic species.
For iso-electronic system,
r∝1Zeffective
So, ionic radius decrease on increasing atomic number for isoelectronic species.
Hence, from the options we can say option (a) is the correct answer.
Na+−1.02 ∘AMg2+−0.72 ∘AAl3+−0.54 ∘A