Question

The ionisation energy and electron affinity of an element are $13eV$ and $3.8eV$ respectively. Find the electronegativity of this element on Pauling's scale.

Answer 1

On Mulliken scale, $E.N.=\frac{I.E+E.A}{2}=\frac{13+3.8}{2}=8.4$
Mulliken values are nearly 2.8 time larger than Pauling value
So, on Pauling scale $=\frac{8.4}{2.8}=3$