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Question

The ionisation enthalpies of atoms A and B are 400 and 300 $k c a l m o l^{- l}$ respectively. The electron gain enthalpies of these atoms are 80.0 and 85.0 $k c a l m o l^{- l}$ respectively. Which of the atoms has a higher electronegativity?

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Both have same electronegativity

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Can't be predicted

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Solution

The correct option is A A
$Electronegativity = \frac{Ionisation energy + Electron affinity}{2}$
Since units are in $k c a l m o l^{- 1}$ , we need to convert it. The formula is applicable when I.E and E.A are given in eV/atom. So,
$X_{A}$ = $\frac{400 + 80}{2 \times 62.5}$ = 3.84

$X_{B}$ = $\frac{300 + 85}{2 \times 62.5}$ = 3.08
Hence, electronegativity of A is greater than that of B.

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Trend in Electronegativity

Standard XI Chemistry

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The ionisation enthalpies of atoms A and B are 400 and 300 kcal mol−l respectively. The electron gain enthalpies of these atoms are 80.0 and 85.0 kcal mol−l respectively. Which of the atoms has a higher electronegativity?

The ionisation enthalpies of atoms A and B are 400 and 300 $k c a l m o l^{- l}$ respectively. The electron gain enthalpies of these atoms are 80.0 and 85.0 $k c a l m o l^{- l}$ respectively. Which of the atoms has a higher electronegativity?