MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Nature of Electromagnetic Radiation

The ionizatio...

Question

The ionization energy of an electron present in the second Bohr's orbit of hydrogen is:

A

54.4 e V

No worries! We‘ve got your back. Try BYJU‘S free classes today!

B

13.6 e V

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C

1.5 e V

No worries! We‘ve got your back. Try BYJU‘S free classes today!

D

3.4 e V

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is C $3.4 e V$
In the second orbit, $n = 2$
$∴$ Ionisation energy $E = - \frac{13.6}{{(2)}^{2}}$
$= - \frac{13.6}{4} = 3.4 e V$

Suggest Corrections

thumbs-up

0

Similar questions

E_{4} = - 0.85 e V

E_{3} = - 1.5 e V

E_{2} = - 3.4 e V

E_{1} = - 13.6 e V

Consider the electron energy level diagram for hydrogen as shown above.
An electron in the ground state of hydrogen atom has an energy of -13.6eV. and 0 eV is the highest energy level present in a hydrogen atom. Identify which of the following energies not possible by photon emitted from hydrogen?

Q. The energy of an electron present in Bohr’s second orbit of hydrogen atom is

Q. Calculate the energy of an electron present in Bohr's second orbit of hydrogen atom in

k J m o l^{- 1}

.

Q. The energy of an electron in the Bohr's first orbit of

H

- 13.6 e V

. The possible energy value (s) of the excited state (s) for electrons in Bohr's orbits of hydrogen is (are):

Q. The ionization energy of the hydrogen atom is

13.6 e V

. Following Bohr's theory, the energy corresponding to a transition between the

3^{r d}

4^{t h}

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Wave Nature of Light

CHEMISTRY

Watch in App

explore_more_icon

Explore more

Nature of Electromagnetic Radiation

Standard XII Chemistry

Join BYJU'S Learning Program

CrossIcon