MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Trends in MPT

The ionizatio...

Question

The ionization energy of the electron in the lowest orbit of hydrogen atom is 13.6ev .The energy required in eV to remove electron from these ionization orbits of hydrogen are

Open in App

Solution

Suggest Corrections

thumbs-up

1

Similar questions

Q. The ionization energy of the electron in the lowest orbit of hydrogen atom is 13.6 eV. The energies required in eV to remove electron from three lowest orbits of hydrogen atom are?

Q. The ionization potential of a hydrogen atom is

13.6 eV

. The energy required to remove an electron from the second orbit of a hydrogen atom is:

Q. The ionization potential of the hydrogen atom is

13.6 volt

. The energy required to remove an electron from the second orbit of hydrogen is:

Q. If the ionization potential of hydrogen atom is 13.6 eV, the energy required to remove from the third orbit of hydrogen atom is

\frac{k}{2 e V}

. Find the value of k ___

Q. In the lowest orbit,the binding energy of an electron in hydrogen atom is

13.6 e V

. The energy required to take out the electron from the lower three orbits (in

e V

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

CHEMISTRY

Watch in App

explore_more_icon

Explore more

Standard VIII Chemistry

Join BYJU'S Learning Program

CrossIcon