The ionization potential of an element is 5.23eV. This can also be expressed as (in kcals/mole) :

120.6

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Solution

The correct option is B $120.6$
The ionization potential of an element is 5.23 eV. This can also be expressed as $120.6$ kcal/mole.
$1 e v = 3.83 \times 10^{- 23}$ kcal
Hence, $5.23 e V = 5.23 e V \times \frac{3.83 \times 10^{- 23} k c a l}{1 e V} = 20 \times 10^{- 23}$ kcal
This is true for 1 atom. For 1 mole, the ionisation energy will be $20 \times 10^{- 23} \times 6.023 \times 10^{23} = 120.6$ kcal/mol.

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