The IP1, IP2, IP3, IP4 and IP5 of an element are 7.1, 14.3, 34.5, 46.8, 162.2 eV respectively. The element is likely to be -

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Solution

The correct option is B
Si

Among the I.P given there is a huge jump from I. $P_{4}$ to I. $P_{5}$ , which shows that element attains stable inert gas configuration after loosing 4 electrons. It should be an element from $14^{t h}$ group (IVA),Si

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Similar questions

The $I P_{1}, I P_{2}, I P_{3}, I P_{4}, I P_{5}$ of an element are 7.1, 14.3, 34.5, 46.8, 162.2 eV respectively. Which element among the following would that be?

Q. The

{I P}_{1}, {I P}_{2}, {I P}_{3}, {I P}_{4}

and

{I P}_{5}

of an element are

7.1, 14.3, 34.5, 46.8, 162.2 e V

respectively.

The element is likely to be:

Q. The

I P_{1^{'}} I P_{2^{'}} I P_{3^{'}} I P_{4^{'}}

and

I P_{5}

of an element are

7.1, 14.3, 34.5, 46.8, 162.2

eV respectively. The element is likely to be:

The $I P_{1}, I P_{2}, I P_{3}, I P_{4}, I P_{5}$ of an element are 7.1, 14.3, 34.5, 46.8, 162.2 eV respectively. Which element among the following would that be?

Q. Sucessive ionisation energies of an element 'X' are given below (in K. Cal)

$I P_{1}$	$I P_{2}$	$I P_{3}$	$I P_{4}$
165	195	556	595

Electronic configuration of the element 'X' is:

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The IP1, IP2, IP3, IP4 and IP5 of an element are 7.1, 14.3, 34.5, 46.8, 162.2 eV respectively. The element is likely to be -

The correct option is B Si Among the I.P given there is a huge jump from I.P4 to I.P5, which shows that element attains stable inert gas configuration after loosing 4 electrons. It should be an element from 14th group (IVA),Si

The correct option is B
Si

Among the I.P given there is a huge jump from I. $P_{4}$ to I. $P_{5}$ , which shows that element attains stable inert gas configuration after loosing 4 electrons. It should be an element from $14^{t h}$ group (IVA),Si