The IUPAC name of:

$C H_{3} - C H_{3} | C = C H - C O O H$

2 - methyl - 2 - butenoic acid

No worries! We‘ve got your back. Try BYJU‘S free classes today!

3 - methyl -3 - butenoic acid

No worries! We‘ve got your back. Try BYJU‘S free classes today!

3- methylbut-2-enoic acid

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

2 - methyl - 3 - butenoic acid

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is D 3- methylbut-2-enoic acid
$C H_{3} - C H_{3} | C = C H - C O O H$
$4$ $3$ $2$ $1$

The IUPAC name of the given compound is 3-methylbut-2-enoic acid.

The longest continuous chain contains 4 C atoms so it is considered as a derivative of butane.

A $C = C$ double bond is present between the second and third C atom.

Hence, butane is replaced with 2-butene. A carboxylic group (-COOH) is present on the first C atom. Hence, 2-butene is replaced with 2 - butenoic acid.

A methyl substituent is present on third C atom which is named as a prefix.

Option C is correct.

Suggest Corrections

Similar questions

C H_{3} - C (C O O C_{2} H_{5}) = C H - C O O H

C H_{3} - C H_{3} | C H - C H = C H_{2}

C H_{3} - C H (C H_{3}) - C H_{2} - C \equiv C - C H_{3}

The IUPAC name of the compound $(C H_{3})_{2} C H C H_{2} C H_{2} C l$ is?

Join BYJU'S Learning Program