Question

The IUPAC name of ${\left[CuC{l}_4\right]}^{2-}$ is tetrachlorido cuprate (II).

• A. True
• B. False

Answer 1

The correct option is A True

True. $[CuC{l}_4{]}^{-2}$

Here, chlorine is the ligand and there are $4$ chlorine molecules. Chlorine is written as chlorido.

Oxidation state is $x+4(-1)=-2$

$x-4=-2$

$x=+2$

So, IUPAC name is tetrachlorido cuprate (II)