The $K_{a}$ values of alcohols, water and phenol are of order $10^{17}, 10^{14}$ and $10^{10}$ respectively. Which of the following reactions is possible?

$(I) C_{6} H_{5} O^{⊝} + H_{2} O \to C_{6} H_{5} O H + O H^{⊝}$
$(I I) C_{2} H_{5} O^{⊝} + H_{2} O \to C_{2} H_{5} O H + O H^{⊝}$

Both I and II

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Only II

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Only I

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Neither of two

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Solution

The correct option is B Only II

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Similar questions

R - O H + H C l {Z n C l}_{2} - --- \to R - C l + H_{2} O

H_{2} O + H_{2} O ⟶ H_{3} O^{+} + O H^{-}

{S_{N}}^{2}

H_{2} O

^{-} O C H_{3},^{-} O H

C H_{3} C O O^{-}

Phenols and alcohols both have same -OH group but still phenols are sparingly soluble in water. This is because:

{C O}_{3}^{2 -} + H_{2} O ⇌ {H C O}_{3}^{-} + {O H}^{-}

{C O}_{2} + H_{2} O ⇌ H_{2} {C O}_{3}

{N H}_{3} + H_{2} O ⇌ {N H}_{4} O H

H C l + H_{2} O ⇌ {C l}^{-} + H_{3} O^{+}

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