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Kepler's Law

The kinetic e...

Question

The kinetic energies of a planet in an elliptical orbit about the Sun, at positions $A, B$ and $C$ are $K_{A}$ , $K_{B}$ and $K_{C}$ respectively. $A C$ is the major axis and $S B$ is perpendicular to $A C$ at the position of the Sun $S$ as shown in the figure. Then.

A

K_{B} < K_{A} < K_{C}

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B

K_{A} < K_{B} < K_{C}

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C

K_{B} > K_{A} > K_{C}

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D

K_{A} > K_{B} > K_{C}

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Solution

The correct option is D $K_{A} > K_{B} > K_{C}$
Kepler’s Law

$\frac{d A}{d t} =$ constant & $T^{2} \propto r^{3}$

$\frac{d A}{d t} =$ constant so

$K_{A} > K_{B} > K_{C}$

Opiton 4.

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